Lane Thomas has become one of the Nationals’ hottest hitters down the stretch of this season, owner of a .357 batting average, .419 on-base percentage and .991 OPS over his last 13 games. And his leadoff homer Saturday helped set the tone for his team’s 5-3 win over the Marlins.
So why isn’t Thomas in the Nats’ lineup for today’s series finale? Consider the numbers against Miami’s starter this afternoon: Thomas is 0-for-11 with six strikeouts in his career against Sandy Alcantara.
Not that anybody has particularly good numbers against Alcantara, who could be on his way to the first Cy Young Award of his career. But in this case, the numbers are so striking, manager Davey Martinez didn’t want to risk Thomas falling into a slump via one bad game at the plate against an ace.
“He’s been swinging the bat well. And I want him to continue to swing the bat well,” Martinez said with a laugh. “I saw the numbers as well, and I thought he’s been playing every day. He’s been playing a lot. I know we’ve had some days off, but I thought give him a day, a little breather, and keep him going.”
Indeed, Thomas has started 30 consecutive games, so he certainly has earned a day off at this point. But he’s also been quite productive during this stretch. Over his last 28 games, he’s batting .310 with seven doubles, a triple, six homers, 14 RBIs and a .913 OPS.